What is the gravitational acceleration of a black hole AT the event horizon? Is it the same for any size black holes, or can it be different. What is the gravitational acceleration of a black hole AT the event horizon?
That would all depend on the size and mass of the singularity at the center.
The curious thing is that with small black holes, the tidal force at the event horizon will rip you to shreds (spaghettificiation). But very large, supermassive black holes have their event horizon quite a ways from the singularity. And the tidal forces aren't as severe, so you can pass it without undue stress. Of course, once you're in, you're in.
It depends on the mass of the black hole.
It's interesting that people talk about the size of a black hole. Singularities have no size. The event horizon has a size, of course.
What is the gravitational acceleration of a black hole AT the event horizon?
It doesn't depend on the size but the distance between an object and the black hole. The distance point from where an object could scape it is called Event Horizont and the distance is the Schwartzchild Radius:
Rs = 2GM / c^2, being c the velocity of the light
I think your second question is solved too
I wish we stay away
Well you know that the escape velocity at the event horizon is the speed of light, so if you remember...escape velocity = square root(2*g*r)... so g = (c^2)/(2r) where r is the radius of the event horizon, c is the speed of light, and g is the gravitational acceleration.What is the gravitational acceleration of a black hole AT the event horizon?
You have to define acceleration first, which is not so easy in General Relativity. However, a stationary observer standing on a platform just above the event horizon observes all infalling bodies to cross the event horizon at c.
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